Question

given the function $f(x)=x^2 - 4$ complete the table.\

$x$	$f(x)$	\
---	---	\
-4		\
-2		\
0		\
3

Explanation:

Step1: Calculate f(-4)

Substitute \( x = -4 \) into \( f(x) = x^2 - 4 \).
\( f(-4) = (-4)^2 - 4 = 16 - 4 = 12 \)

Step2: Calculate f(-2)

Substitute \( x = -2 \) into \( f(x) = x^2 - 4 \).
\( f(-2) = (-2)^2 - 4 = 4 - 4 = 0 \)

Step3: Calculate f(0)

Substitute \( x = 0 \) into \( f(x) = x^2 - 4 \).
\( f(0) = 0^2 - 4 = 0 - 4 = -4 \)

Step4: Calculate f(3)

Substitute \( x = 3 \) into \( f(x) = x^2 - 4 \).
\( f(3) = 3^2 - 4 = 9 - 4 = 5 \)

Answer:

\( x \)	\( f(x) \)
-2	0
0	-4
3	5