QUESTION IMAGE
Question
- given: $overline{ab}congoverline{cd}$, $overline{bd}congoverline{de}$
prove: $overline{ad}congoverline{ce}$
| statements | reasons |
|---|---|
| 2. | 2. definition of congruence |
| 3. $ab + bd=ad$ | 3. |
| 4. $cd + de=ad$ | 4. |
| 5. | 5. segment addition postulate |
| 6. $ad = ce$ | 6. |
| 7. | 7. definition of congruence |
Step1: Write congruence as equal - length
Since $\overline{AB}\cong\overline{CD}$ and $\overline{BD}\cong\overline{DE}$, by the definition of congruence, $AB = CD$ and $BD=DE$.
Step2: Apply segment - addition postulate
By the segment - addition postulate, for collinear points $A$, $B$, and $D$, $AB + BD=AD$.
Step3: Substitute equal lengths
Since $AB = CD$ and $BD = DE$, we can substitute into the equation $AB + BD=AD$ to get $CD + DE=AD$. Also, for collinear points $C$, $D$, and $E$, by the segment - addition postulate, $CD + DE=CE$.
Step4: Transitive property
Since $CD + DE=AD$ and $CD + DE=CE$, by the transitive property of equality, $AD = CE$.
Step5: Write as congruence
By the definition of congruence, if $AD = CE$, then $\overline{AD}\cong\overline{CE}$.
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| Statements | Reasons |
|---|---|
| 2. $AB = CD$, $BD = DE$ | 2. Definition of Congruence |
| 3. $AB + BD=AD$ | 3. Segment Addition Postulate |
| 4. $CD + DE=AD$ (by substitution from step 2 into step 3) | 4. Substitution Property |
| 5. $CD + DE=CE$ | 5. Segment Addition Postulate |
| 6. $AD = CE$ | 6. Transitive Property of Equality |
| 7. $\overline{AD}\cong\overline{CE}$ | 7. Definition of Congruence |