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Question
given: $overline{ps}paralleloverline{qr}$, $angle qpscongangle srq$. prove: $overline{pq}congoverline{rs}$. statements 1. $overline{ps}paralleloverline{qr}$, $angle qpscongangle srq$ 2. $overline{qs}congoverline{qs}$ 3. $angle psqcongangle sqr$ 4. $\triangle psqcong\triangle rqs$ 5. $overline{pq}congoverline{rs}$. reasons 1. given 2. 3. 4. 5.
Step1: Reflexive property
Any segment is congruent to itself, so $\overline{QS}\cong\overline{QS}$.
Step2: Alternate - interior angles
Since $\overline{PS}\parallel\overline{QR}$, the alternate - interior angles $\angle PSQ$ and $\angle SQR$ are congruent.
Step3: Angle - Side - Angle (ASA) congruence
We have $\angle QPS\cong\angle SRQ$ (given), $\overline{QS}\cong\overline{QS}$ (reflexive property), and $\angle PSQ\cong\angle SQR$ (alternate - interior angles), so $\triangle PSQ\cong\triangle RQS$ by ASA.
Step4: Corresponding parts of congruent triangles
If $\triangle PSQ\cong\triangle RQS$, then the corresponding sides $\overline{PQ}$ and $\overline{RS}$ are congruent.
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- Reflexive property
- Alternate - interior angles
- ASA (Angle - Side - Angle)
- Corresponding parts of congruent triangles (CPCTC)