Question

1. given that segment de is a midsegment of δabc, find the following. ad = de =

Explanation:

Step1: Recall mid - segment property for AD

A mid - segment divides the side it intersects in half. Since AB = 13 and D is the mid - point of AB (because DE is a mid - segment), then $AD=\frac{AB}{2}=\frac{13}{2}=6.5$.

Step2: Recall mid - segment property for DE

The length of a mid - segment of a triangle is half the length of the third side of the triangle. Since AC = 10 and DE is a mid - segment parallel to AC, then $DE=\frac{AC}{2}=\frac{10}{2}=5$.

Answer:

AD = 6.5, DE = 5