Question

a golf ball is hit with an initial velocity of 130 feet per second at an inclination of 45° to the horizontal. in physics, it is established that the height h of the golf ball is given by the function h(x)=\frac{-32x^{2}}{130^{2}}+x, where x is the horizontal distance that the golf ball has traveled. complete parts (a) through (g). (f) use a graphing utility to determine the distance that the ball has traveled when the height of the ball is 90 feet. choose the correct answer below and, if necessary, fill in the answer box to complete your choice. a. the ball has traveled 115.07, 413.05 feet. (use a comma to separate answers as needed. round to two decimal places as needed.) b. the ball has not traveled. (g) create a table with tblstart = 0 and δtbl = 25. to the nearest 25 feet, how far does the ball travel before it reaches a maximum height? what is the maximum height? to the nearest 25 feet, the ball travels feet.

Explanation:

Step1: Recall the height - function

The height function of the golf - ball is $h(x)=\frac{-32x^{2}}{130^{2}}+x$.

Step2: For part (g), find the vertex of the parabola

The function $h(x)$ is a quadratic function in the form $y = ax^{2}+bx + c$, where $a=\frac{-32}{130^{2}}$ and $b = 1$. The x - coordinate of the vertex of a quadratic function $y=ax^{2}+bx + c$ is given by $x=-\frac{b}{2a}$.
First, calculate $a=\frac{-32}{130^{2}}=\frac{-32}{16900}\approx - 0.001893$.
Then, $x=-\frac{1}{2\times\frac{-32}{16900}}=\frac{16900}{64}=264.0625$.
Rounding $264.0625$ to the nearest 25 feet, we consider the multiples of 25: 250, 275. Since $264.0625$ is closer to 275.

Answer:

275