Question

graph the image of square bcde after a rotation 270° clockwise around the origin.

Explanation:

Step1: Recall rotation rule

The rule for a 270 - degree clockwise rotation around the origin is $(x,y)\to(y, - x)$.

Step2: Identify original coordinates

Let's assume the coordinates of the vertices of square $BCDE$ are $B(6,-3)$, $C(8,-3)$, $D(8,0)$, $E(6,0)$.

Step3: Apply rotation rule to $B$

For point $B(6,-3)$, using the rule $(x,y)\to(y, - x)$, we get $B'(-3,-6)$.

Step4: Apply rotation rule to $C$

For point $C(8,-3)$, we have $C'(-3,-8)$.

Step5: Apply rotation rule to $D$

For point $D(8,0)$, we get $D'(0,-8)$.

Step6: Apply rotation rule to $E$

For point $E(6,0)$, we get $E'(0,-6)$.

Step7: Graph new points

Plot the points $B'(-3,-6)$, $C'(-3,-8)$, $D'(0,-8)$, $E'(0,-6)$ on the coordinate - plane and connect them to form the rotated square.

Answer:

Graph the points $B'(-3,-6)$, $C'(-3,-8)$, $D'(0,-8)$, $E'(0,-6)$ and connect them to get the rotated square.