Question

graph the line that has a slope of 4 and includes the point (0, -9). click to select points on the graph.

Explanation:

Step1: Recall the slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. Given $m = 4$ and the point $(0,-9)$ which is the y - intercept (since when $x = 0$), so $b=-9$. The equation of the line is $y = 4x-9$.

Step2: Find another point

Let $x = 1$. Then $y=4\times1 - 9=-5$. So another point on the line is $(1,-5)$.

Step3: Graph the line

Plot the points $(0,-9)$ and $(1,-5)$ on the coordinate plane and draw a straight line passing through them.

Answer:

Plot the points $(0,-9)$ and $(1,-5)$ and draw a straight - line through them.