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graph the parabola $y = 7x^2$. plot the vertex. then plot another point…

Question

graph the parabola $y = 7x^2$. plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first.

Explanation:

Step1: Find the vertex

For $y=ax^2$, vertex is $(0,0)$.

Step2: Find a second point

Substitute $x=1$: $y=7(1)^2=7$, so point $(1,7)$.

Step3: Plot and sketch parabola

Plot $(0,0)$ and $(1,7)$, mirror for $(-1,7)$, then draw symmetric curve.

Answer:

  1. Vertex at the coordinate $(0, 0)$
  2. Additional point at $(1, 7)$ (or $(-1, 7)$), with a symmetric, upward-opening parabola passing through these points.