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the graph shows the ages of different concertgoers who have backstage p…

Question

the graph shows the ages of different concertgoers who have backstage passes. which statement is true about the graph? a late arrival who is 21 years old with a back - stage pass will make the mean greater than the median. the two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age. the ages of concert - goers with backstage passes are skewed left, so the mean age is less than the median age. a concert - goer who is 18 years old and wins a back - stage pass will pull the mean more than 2 years less than the median.

Explanation:

Step1: Recall mean - median relationship in skewed data

In a right - skewed distribution, the mean is greater than the median; in a left - skewed distribution, the mean is less than the median. The given histogram has a tail on the right (higher ages), so it is right - skewed.

Step2: Analyze each option

  • Option A: A 21 - year - old is around the peak of the distribution. Adding a value around the peak will not make the mean greater than the median as the existing distribution is already right - skewed.
  • Option B: The two holders of back - stage passes whose ages are above 40 are in the right - tail of the distribution. In a right - skewed distribution, extreme values in the right - tail pull the mean upwards, making the mean age higher than the median age. This is correct.
  • Option C: The ages are skewed right, not left. So, this option is incorrect.
  • Option D: An 18 - year - old is around the peak of the distribution. Adding an 18 - year - old will not pull the mean more than 2 years less than the median.

Answer:

The two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age.