Question

graph: $f(x) = 4^x$
step 1: calculate the initial value of the function.
$f(0) = 4^0 = 1$
step 2: plot the initial value of the function at (0, 1).
step 3: evaluate the function at two more points.
$f(1) = 4^1 = 4$ ; $f(-1) = 4^{-1} = 1/4$
step 4: plot the points (1, 4) and (-1, 1/4).
(there is also a coordinate plane with some plotted points and a table with x=0,y=1 and x=1,y=4 shown)

Explanation:

Step1: Evaluate $f(-1)$

Substitute $x=-1$ into $f(x)=4^x$:
$f(-1)=4^{-1}=\frac{1}{4}$

Step2: Choose another $x$-value, e.g., $x=2$

Substitute $x=2$ into $f(x)=4^x$:
$f(2)=4^2=16$

Step3: Identify the new point

The point is $(2, 16)$

Answer:

The additional point to plot is $(2, 16)$ (alternatively, $(-1, \frac{1}{4})$ is another completed point from Step 3; the fully filled table would be:

$x$	$y$
1	4
-1	$\frac{1}{4}$
2	16

And the graph includes points $(0,1)$, $(1,4)$, $(-1, \frac{1}{4})$, and $(2,16)$)