Question

graphing linear equations
vectored instruction
graph the
equation by filling
in the chart.
equation:
$y = 10 - 2x$

x	y
1
2
3
4

Explanation:

Step1: Substitute x = 0 into the equation

We have the equation \( y = 10 - 2x \). When \( x = 0 \), we substitute \( x \) with 0 in the equation.
\( y = 10 - 2\times0 \)

Step2: Simplify the expression

Calculate \( 2\times0 = 0 \), then \( y = 10 - 0 = 10 \).

For \( x = 1 \):

Step1: Substitute x = 1 into the equation

\( y = 10 - 2\times1 \)

Step2: Simplify the expression

\( 2\times1 = 2 \), so \( y = 10 - 2 = 8 \).

For \( x = 2 \):

Step1: Substitute x = 2 into the equation

\( y = 10 - 2\times2 \)

Step2: Simplify the expression

\( 2\times2 = 4 \), so \( y = 10 - 4 = 6 \).

For \( x = 3 \):

Step1: Substitute x = 3 into the equation

\( y = 10 - 2\times3 \)

Step2: Simplify the expression

\( 2\times3 = 6 \), so \( y = 10 - 6 = 4 \).

For \( x = 4 \):

Step1: Substitute x = 4 into the equation

\( y = 10 - 2\times4 \)

Step2: Simplify the expression

\( 2\times4 = 8 \), so \( y = 10 - 8 = 2 \).

Answer:

When \( x = 0 \), \( y = 10 \); when \( x = 1 \), \( y = 8 \); when \( x = 2 \), \( y = 6 \); when \( x = 3 \), \( y = 4 \); when \( x = 4 \), \( y = 2 \). So the completed table is:

X	Y
1	8
2	6
3	4
4	2