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graphing a quadratic function in vertex form graph ( h(x) = 0.5(x + 2)^…

Question

graphing a quadratic function in vertex form
graph ( h(x) = 0.5(x + 2)^2 - 4 ) by following these steps:
step 1: identify ( a ), ( h ), and ( k )
( a = 0.5 ), ( h = -2 ), ( k = ) dropdown with -4 and 4 options

Explanation:

Step1: Recall vertex form

The vertex form of a quadratic function is $h(x)=a(x-h)^2+k$.

Step2: Match given function

For $h(x)=0.5(x+2)^2-4$, rewrite $(x+2)$ as $(x-(-2))$.
So $a=0.5$, $h=-2$, $k=-4$.

Answer:

$k=-4$