Question

gravity
gravity on earth can be simply represented as a (g). the strength of gravity, this g, is the rate at which objects accelerate through space. on earth this is:
\\(g = 9.81\space m/s^2\\)
this means that if something is falling, it will keep speeding up (accelerating). before an object is falling, the rate is zero. after one second at a speed of 9.81 m/s and after 2 seconds, the object will moving be moving faster 19.62 m/s, and keeps getting faster and faster! so if you try to catch something thrown out of a second story window, it might not be going that fast when you catch it. if you try to catch something thrown out of the 50th floor, watch out, its moving very fast.
question: how fast will an object be moving after 10 seconds?

Explanation:

Step1: Identify the formula for speed under gravity

The speed \( v \) of an object in free fall (assuming initial velocity \( u = 0 \)) is given by the formula \( v=u + gt \). Since the initial velocity \( u = 0 \) (before falling, the rate is zero), the formula simplifies to \( v = gt \).

Step2: Substitute the values of \( g \) and \( t \)

We know that \( g = 9.81\space m/s^{2} \) and \( t = 10\space s \). Substituting these values into the formula \( v=gt \), we get \( v=9.81\times10 \).

Step3: Calculate the result

\( 9.81\times10 = 98.1 \).

Answer:

The object will be moving at a speed of \( 98.1\space m/s \) after 10 seconds.