Question

green plants use light from the sun to drive photosynthesis. photosynthesis is a chemical reaction in which water (h₂o) and carbon dioxide (co₂) chemically react to form the simple sugar glucose (c₆h₁₂o₆) and oxygen gas (o₂). what mass of simple sugar glucose is produced by the reaction of 6.56 g of water? be sure your answer has the correct number of significant digits.

Explanation:

Step1: Write balanced chemical equation

$$6H_2O + 6CO_2 ightarrow C_6H_{12}O_6+6O_2$$

Step2: Calculate molar - mass of water and glucose

The molar mass of $H_2O$ is $M_{H_2O}=(2\times1.01 + 16.00)\text{ g/mol}=18.02\text{ g/mol}$. The molar mass of $C_6H_{12}O_6$ is $M_{C_6H_{12}O_6}=(6\times12.01+12\times1.01 + 6\times16.00)\text{ g/mol}=180.18\text{ g/mol}$.

Step3: Determine mole of water

$n_{H_2O}=\frac{m_{H_2O}}{M_{H_2O}}=\frac{6.56\text{ g}}{18.02\text{ g/mol}}\approx0.364\text{ mol}$

Step4: Use mole - ratio to find mole of glucose

From the balanced equation, the mole - ratio of $H_2O$ to $C_6H_{12}O_6$ is $6:1$. So, $n_{C_6H_{12}O_6}=\frac{1}{6}n_{H_2O}=\frac{1}{6}\times0.364\text{ mol}\approx0.0607\text{ mol}$

Step5: Calculate mass of glucose

$m_{C_6H_{12}O_6}=n_{C_6H_{12}O_6}\times M_{C_6H_{12}O_6}=0.0607\text{ mol}\times180.18\text{ g/mol}\approx10.9\text{ g}$

Answer:

$10.9\text{ g}$