Question

hcl + naoh → nacl + h₂o
25.0 ml of 1.00 m hcl is added to
75.0 ml of 1.00 m naoh. the
resulting temperature change is an
increase of 8.65 °c.
csol = 4.20 j/g °c dsol = 1.02 g/ml
what is the mass of the solution?
masssol = ? g

Explanation:

Step1: Calculate total volume of solution

The volume of HCl is 25.0 mL and the volume of NaOH is 75.0 mL. So the total volume \( V \) of the solution is the sum of these two volumes.
\( V = 25.0\ mL + 75.0\ mL = 100.0\ mL \)

Step2: Use density formula to find mass

The density formula is \(
ho=\frac{m}{V} \), where \(
ho \) is density, \( m \) is mass, and \( V \) is volume. Rearranging for mass, we get \( m =
ho\times V \). Given \(
ho = d_{sol}=1.02\ g/mL \) and \( V = 100.0\ mL \).
\( m = 1.02\ g/mL\times100.0\ mL = 102\ g \)

Answer:

102