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from his home, justin would have to walk due north to get to his friend…

Question

from his home, justin would have to walk due north to get to his friend hassan’s house and due east to get to his friend ellen’s house. it is 4 miles from justin’s house to ellen’s house and a straight - line distance of 5 miles from hassan’s house to ellen’s house. how far is justin’s house from hassan’s house?
□ miles

Explanation:

Step1: Identify right triangle sides

Let Justin's home = $J$, Hassan's = $H$, Ellen's = $E$. $JH = x$ (unknown), $JE = 4$, $HE = 5$. $\triangle JHE$ is right-angled at $J$.

Step2: Apply Pythagorean theorem

$$JH^2 + JE^2 = HE^2$$
$$x^2 + 4^2 = 5^2$$

Step3: Solve for $x$

$$x^2 = 25 - 16 = 9$$
$$x = \sqrt{9} = 3$$

Answer:

3 miles