Question

homework chapter 2 question 17 of 17 (6 points) | question attempt: 1 of unlimited

• that is, select group 1 next to all the compounds with the first empirical formula. (if all four compounds have the same empirical formula, then theyll all end up in group 1.)
• next, select group 2 next to all the compounds with the second empirical formula. and so on.
• if all four compounds have different empirical formulas, then theyll each end up alone in their own group: compound a will be alone in group 1, compound b will be alone in group 2, and so on.

about the sketches: the lines stand for chemical bonds between the atoms. just ignore the dots. they stand for \lone pairs,\ and youll learn about them later.
compound sketch of molecules in it group
a h - o - c - c - h h - c - c - o - h h h h h select
b h - o - c - o - c - o - h h - c - c - o - h h h h h select
c h - c = c - o - h h h select
try again
recheck save for later submit assignm

Explanation:

Step1: Determine empirical formula concept

The empirical formula gives the simplest whole - number ratio of atoms in a compound.

Step2: Count atoms in Compound A

Count C, H, and O atoms. Assume the structure of Compound A has 4 C, 10 H, 2 O. The ratio of C : H : O is 4:10:2, which simplifies to 2:5:1. The empirical formula is $C_2H_5O$.

Step3: Count atoms in Compound B

Count C, H, and O atoms. Assume the structure of Compound B has 4 C, 10 H, 4 O. The ratio of C : H : O is 4:10:4, which simplifies to 2:5:2. The empirical formula is $C_2H_5O_2$.

Step4: Count atoms in Compound C

Count C, H, and O atoms. Assume the structure of Compound C has 2 C, 4 H, 1 O. The ratio of C : H : O is 2:4:1. The empirical formula is $C_2H_4O$.

Step5: Group compounds

Since all three compounds have different empirical formulas, Compound A is in Group 1, Compound B is in Group 2, Compound C is in Group 3.

Answer:

Compound A: Group 1
Compound B: Group 2
Compound C: Group 3