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homework: section 2.4 due jan 26 by 11:59pm points 12 submitting an ext…

Question

homework: section 2.4 due jan 26 by 11:59pm points 12 submitting an external tool homework: section 2.4 score: 4.8/9 answered: 6/9 question 8 the five - number summary of a dataset was calculated to be 0, 2, 7, 15, 19 a. an observation is considered an outlier if it is below. b. an observation is considered an outlier if it is above.

Explanation:

Step1: Identify quartiles from 5-number summary

Five-number summary: $Q_1=2$, $Q_3=15$

Step2: Calculate interquartile range (IQR)

$IQR = Q_3 - Q_1 = 15 - 2 = 13$

Step3: Find lower outlier threshold

Lower bound = $Q_1 - 1.5 \times IQR = 2 - 1.5 \times 13 = 2 - 19.5 = -17.5$

Step4: Find upper outlier threshold

Upper bound = $Q_3 + 1.5 \times IQR = 15 + 1.5 \times 13 = 15 + 19.5 = 34.5$

Answer:

a. $-17.5$
b. $34.5$