Question

hour: 3x < \frac{1}{2}(4x + 4)

Explanation:

Step1: Expand the right - hand side

$3x<\frac{1}{2}(4x + 4)$ becomes $3x<2x + 2$.

Step2: Subtract $2x$ from both sides

$3x-2x<2x + 2-2x$.

Step3: Simplify

$x<2$.

Answer:

$x < 2$