Question

how to calculate volume of concentrated solution needed to prepare a diluted solution

1. how many milliliters of the approximately 0.12 m prepared copper(ii) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.012 m copper(ii) sulfate solution?

_______ ml

Explanation:

Step1: Recall dilution formula

The dilution formula is $C_1V_1 = C_2V_2$, where $C_1$ = initial concentration, $V_1$ = initial volume, $C_2$ = final concentration, $V_2$ = final volume.

Step2: Identify known values

$C_1 = 0.12\ M$, $C_2 = 0.012\ M$, $V_2 = 100.00\ mL$

Step3: Solve for $V_1$

Rearrange formula to $V_1 = \frac{C_2V_2}{C_1}$
Substitute values: $V_1 = \frac{0.012\ M \times 100.00\ mL}{0.12\ M}$

Step4: Calculate the result

$V_1 = \frac{1.2}{0.12}\ mL = 10.00\ mL$

Answer:

10.00 mL