Question

how many equivalents of hydrochloric acid would react with 0.248 eq calcium hydroxide?

Explanation:

Step1: Write neutralization reaction

$$\text{Ca(OH)}_2 + 2\text{HCl} ightarrow \text{CaCl}_2 + 2\text{H}_2\text{O}$$

Step2: Relate acid-base equivalents

For neutralization, equivalents of acid = equivalents of base.
$$\text{Eq of HCl} = \text{Eq of Ca(OH)}_2$$

Step3: Substitute given value

$$\text{Eq of HCl} = 0.248$$

Answer:

0.248 equivalents