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Question
how many solutions does this equation have? 20d + 16 = -20d - 8(-5d - 2) no solution one solution infinitely many solutions
Step1: Expand the right-hand side
$20d + 16 = -20d - 8(-5d) - 8(-2)$
$20d + 16 = -20d + 40d + 16$
Step2: Simplify like terms on RHS
$20d + 16 = 20d + 16$
Step3: Subtract $20d+16$ from both sides
$20d + 16 - (20d + 16) = 20d + 16 - (20d + 16)$
$0 = 0$
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infinitely many solutions