Question

how many total atoms? (nh4)3po4+pb(no3)4=pb3(po4)4+nh4no3

Explanation:

Step1: Analyze the reactants and products for atom - counting.

Count atoms in each compound. In \((NH_4)_3PO_4\):

• \(N\): \(3\) atoms (since there are 3 \(NH_4\) groups and 1 \(N\) in each \(NH_4\)).
• \(H\): \(4\times3 = 12\) atoms.
• \(P\): \(1\) atom.
• \(O\): \(4\) atoms.

In \(Pb(NO_3)_4\):

• \(Pb\): \(1\) atom.
• \(N\): \(4\) atoms.
• \(O\): \(3\times4=12\) atoms.

In \(Pb_3(PO_4)_4\):

• \(Pb\): \(3\) atoms.
• \(P\): \(4\) atoms.
• \(O\): \(4\times4 = 16\) atoms.

In \(NH_4NO_3\):

• \(N\): \(2\) atoms.
• \(H\): \(4\) atoms.
• \(O\): \(3\) atoms.

Step2: Calculate the total number of atoms.

Sum up the atoms of all elements.

• \(N\): \(3 + 4+2=9\)
• \(H\): \(12 + 4=16\)
• \(P\): \(1+4 = 5\)
• \(O\): \(4+12 + 16+3=35\)
• \(Pb\): \(1+3=4\)

Total atoms \(=9 + 16+5+35+4=69\)

Answer:

69