Question

how much 20 meq/30 ml potassium chloride solution, in ml, will deliver a dose of 6.67 meq?
a. 6.67
b. 10
c. 20
d. 30

Explanation:

Step1: Set up proportion

Let \( x \) be the volume in mL. The proportion is \(\frac{20\ \text{mEq}}{30\ \text{mL}}=\frac{6.67\ \text{mEq}}{x\ \text{mL}}\)

Step2: Cross - multiply

\(20x = 30\times6.67\)

Step3: Solve for \(x\)

\(x=\frac{30\times6.67}{20}\approx\frac{200.1}{20} = 10\) (approximate since \(6.67\approx\frac{20}{3}\), so \(\frac{30\times\frac{20}{3}}{20}=\frac{200}{20} = 10\))

Answer:

B. 10