Question

1. how much of a 0.33 m h2so4 solution is needed to make 500.0 ml 0.075 m solution?

Explanation:

Step1: Recall dilution formula

$M_1V_1 = M_2V_2$

Step2: Identify given values

$M_1=0.33\ M$, $M_2 = 0.075\ M$, $V_2=500.0\ mL$

Step3: Solve for $V_1$

$V_1=\frac{M_2V_2}{M_1}=\frac{0.075\ M\times500.0\ mL}{0.33\ M}$
$V_1=\frac{37.5\ M\cdot mL}{0.33\ M}\approx113.6\ mL$

Answer:

$113.6\ mL$