Question

how much p is required to react with 2.7 grams of be to form 8.9 grams of be3p2?

reaction	reactant(s)	product(s)
mass	2.7 g	?	8.9 g

Explanation:

Step1: Apply the law of conservation of mass

The law of conservation of mass states that the total mass of reactants is equal to the total mass of products in a chemical reaction. Let the mass of P be $x$. Then the sum of the masses of Be and P should equal the mass of $Be_3P_2$. So, $2.7 + x=8.9$.

Step2: Solve for x

To find $x$, we subtract 2.7 from both sides of the equation: $x = 8.9 - 2.7$.

Answer:

$6.2$ g