Question

how can you write $3^{-2}$ using a positive exponent?
$3^{-2}=\frac{1}{3^{2}}$
how can you write $3^{-3}$ using a positive exponent?
$3^{-3}=$ ?
$3^{n}$ value
$3^{3}$ 27
$3^{2}$ 9
$3^{1}$ 3
$3^{0}$ 1
$3^{-1}$ $\frac{1}{3}$
$3^{-2}$ $\frac{1}{9}$
$3^{-3}$ $\frac{1}{27}$

Explanation:

Step1: Recall negative exponent rule

For any non-zero base $a$ and positive integer $n$, $a^{-n} = \frac{1}{a^n}$.

Step2: Apply rule to $3^{-3}$

Substitute $a=3$, $n=3$ into the rule:
$3^{-3} = \frac{1}{3^3}$

Answer:

$\frac{1}{3^3}$