Question

hs math claim 1 - target a (ccss n - rn 1, 2) dok 2
question:
segment ae shown has length $sqrt{20}$.
which segment is closest in length to $sqrt{10}$

Explanation:

Step1: Simplify square - root values

We know that $\sqrt{20}=2\sqrt{5}\approx2\times2.24 = 4.47$ and $\sqrt{10}\approx3.16$.
If we assume the points divide segment $AE$ into approximately equal - length sub - segments. Since segment $AE$ has length $\sqrt{20}$, and we want a segment of length $\sqrt{10}$, which is half of $\sqrt{20}$ approximately.
If we assume the points $B$, $C$, $D$ divide segment $AE$ into 4 equal - length sub - segments (a reasonable assumption without further information), then a segment that is half of $AE$ in length would be a segment composed of 2 of these sub - segments.
Let's assume the sub - segments $AB = BC=CD = DE$. Then a segment composed of 2 of these sub - segments, like $AC$ or $CE$, would be closest to the length of $\sqrt{10}$.

Answer:

Segments $AC$ or $CE$ (assuming equal - length sub - segments between $A$ and $E$)