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Question 6

Step1: Recall Avogadro's number

Avogadro's number is \( 6.02 \times 10^{23} \) particles per mole. To convert atoms to moles, use the formula: \( \text{Moles} = \frac{\text{Number of particles}}{6.02 \times 10^{23}} \)

Step2: Substitute the values

Given \( 3.01 \times 10^{23} \) atoms of magnesium. So, \( \text{Moles} = \frac{3.01 \times 10^{23}}{6.02 \times 10^{23}} \)

Step3: Simplify the expression

\( \frac{3.01 \times 10^{23}}{6.02 \times 10^{23}} = \frac{3.01}{6.02} = 0.5 \)

Step1: Recall Avogadro's number

Avogadro's number is \( 6.02 \times 10^{23} \) particles per mole. To convert molecules to moles, use the formula: \( \text{Moles} = \frac{\text{Number of molecules}}{6.02 \times 10^{23}} \)

Step2: Substitute the values

Given \( 1.81 \times 10^{24} \) molecules of \( \text{CO}_2 \). So, \( \text{Moles} = \frac{1.81 \times 10^{24}}{6.02 \times 10^{23}} \)

Step3: Simplify the expression

\( \frac{1.81 \times 10^{24}}{6.02 \times 10^{23}}=\frac{1.81\times10}{6.02}=\frac{18.1}{6.02}\approx 3.01 \)

Step1: Recall Avogadro's number

Avogadro's number is \( 6.02 \times 10^{23} \) formula units per mole. To convert formula units to moles, use the formula: \( \text{Moles} = \frac{\text{Number of formula units}}{6.02 \times 10^{23}} \)

Step2: Substitute the values

Given \( 4.82 \times 10^{23} \) formula units of \( \text{KBr} \). So, \( \text{Moles} = \frac{4.82 \times 10^{23}}{6.02 \times 10^{23}} \)

Step3: Simplify the expression

\( \frac{4.82 \times 10^{23}}{6.02 \times 10^{23}}=\frac{4.82}{6.02}\approx 0.801 \) (or approximately \( 0.8 \))

Answer:

\( 0.5 \)

Question 7