Question

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Explanation:

(Question 5):

Step1: Calculate total reactant mass

$16\ \text{amu} + 64\ \text{amu} = 80\ \text{amu}$

Step2: Calculate total product mass

$44\ \text{amu} + 36\ \text{amu} = 80\ \text{amu}$

Step3: Compare reactant and product mass

$80\ \text{amu} = 80\ \text{amu}$

(Question 6):

Step1: Find total Fe reactant mass

Let total Fe mass = $m$. By LCM: $m + 213\ \text{amu} = 325\ \text{amu}$
$m = 325\ \text{amu} - 213\ \text{amu} = 112\ \text{amu}$

Step2: Calculate mass of one Fe atom

There are 2 Fe atoms, so:
$\text{Mass of 1 Fe atom} = \frac{112\ \text{amu}}{2} = 56\ \text{amu}$

Answer:

(Question 5):
Yes, the masses obey the Law of Conservation of Mass (LCM). The total mass of reactants ($80\ \text{amu}$) equals the total mass of products ($80\ \text{amu}$), so mass is conserved in the reaction.

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