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Question
ii) add or subtract and reduce if possible:
- \\(\frac{9}{16} + \frac{3}{16}\\)
- \\(\frac{3}{4} - \frac{1}{8}\\)
- \\(\frac{5}{12} + \frac{9}{8}\\)
- \\(\frac{9}{10} - \frac{5}{6}\\)
- \\(\frac{5}{6} + \frac{2}{9}\\)
- \\(\frac{13}{14} - \frac{3}{4}\\)
- \\(\frac{7}{10} + \frac{11}{25}\\)
- \\(\frac{8}{9} - \frac{2}{15}\\)
- \\(\frac{11}{12} + \frac{3}{10}\\)
- \\(\frac{9}{20} - \frac{3}{8}\\)
- \\(\frac{4}{5} + \frac{2}{30}\\)
- \\(\frac{7}{12} - \frac{5}{18}\\)
homework #2: this must be done on loose - leaf paper!
perform the indicated operations and reduce your answers (no mixed numbers):
- \\(\frac{9}{8} \times \frac{20}{63}\\)
- \\(\frac{25}{18} div \frac{15}{24}\\)
- \\(\frac{55}{28} \times \frac{21}{19} \times \frac{38}{66}\\)
- \\(left(\frac{35}{26} div \frac{45}{39}
ight) \times \frac{9}{7}\\)
- \\(left(\frac{8}{9} - \frac{2}{3}
ight) div 4\\)
- \\(\frac{11}{12} - \frac{4}{9}\\)
- \\(\frac{1}{6} + \frac{2}{15}\\)
- \\(\frac{9}{10} - \frac{5}{8}\\)
- \\(\frac{5}{6} + \frac{3}{8}\\)
Let's solve problem 1) in the "Add or subtract and reduce if possible" section: $\frac{9}{16} + \frac{3}{16}$
Step 1: Add the numerators (common denominator)
Since the denominators are the same (16), we add the numerators: $9 + 3 = 12$. The denominator remains 16. So we have $\frac{9 + 3}{16} = \frac{12}{16}$.
Step 2: Reduce the fraction
Find the greatest common divisor (GCD) of 12 and 16. The factors of 12 are 1, 2, 3, 4, 6, 12. The factors of 16 are 1, 2, 4, 8, 16. The GCD is 4. Divide both numerator and denominator by 4: $\frac{12 \div 4}{16 \div 4} = \frac{3}{4}$.
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$\frac{3}{4}$