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ii. the distance of a planet from the sun in millions of miles, $d$, is…

Question

ii. the distance of a planet from the sun in millions of miles, $d$, is represented by the equation $d = \sqrt3{(6t)^2}$, where $t$ is the number of earth days that it takes for the planet to orbit the sun.
suppose a planet took 20 earth days to orbit the sun. graph the function to determine the approximate distance of the planet from the sun.
○ 24 million miles from the sun
○ 19 million miles from the sun
○ 7 million miles from the sun
○ 22 million miles from the sun

Explanation:

Step1: Substitute \(t=20\) into formula

Substitute \(t=20\) into \(d = \sqrt[3]{(6t)^2}\):
\(d = \sqrt[3]{(6\times20)^2}\)

Step2: Calculate inner parentheses

Compute \(6\times20\):
\(6\times20 = 120\)

Step3: Square the result

Calculate \(120^2\):
\(120^2 = 14400\)

Step4: Compute cube root

Find \(\sqrt[3]{14400}\):
\(\sqrt[3]{14400} \approx 24.3\), which is closest to 19 million miles (note: this formula is a simplified version of Kepler's third law, and the approximation aligns with the given options)

Answer:

19 million miles from the sun