Question

ii. evaluate each expression for the given values and circle your answers. 5. $3x^{2}-2y^{2}$ for $x = \frac{1}{4}$ and $y=-\frac{1}{2}$

Explanation:

Step1: Substitute x value

Substitute $x = \frac{1}{4}$ into $3x^{2}$.
$3\times(\frac{1}{4})^{2}=3\times\frac{1}{16}=\frac{3}{16}$

Step2: Substitute y value

Substitute $y =-\frac{1}{2}$ into $2y^{2}$.
$2\times(-\frac{1}{2})^{2}=2\times\frac{1}{4}=\frac{1}{2}$

Step3: Calculate the expression

Subtract the results of step 2 from step 1.
$\frac{3}{16}-\frac{1}{2}=\frac{3}{16}-\frac{8}{16}=-\frac{5}{16}$

Answer:

$-\frac{5}{16}$