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QUESTION IMAGE

imagine 6 in your head double it add 3 write the tens digit. a imagine …

Question

imagine 6 in your head
double it
add 3

write the tens digit.
a

imagine 3 in your head
multiply 6
double it
add 2
subtract 9
add 9
add the tens digit to the ones digit.
write the sum.
b c

imagine 2 in your head
add 4
multiply 8
subtract 7

write the tens digit.
d

imagine 4 in your head
add 1
multiply 11
double it

add the tens digit to the ones digit.
write the sum.
e

Explanation:

Response
First Box (A)

Step1: Double 6

$6\times2 = 12$

Step2: Add 3

$12 + 3 = 15$

Step3: Write the tens digit

The number is 15, tens digit is 1.

Step1: Multiply 3 by 6

$3\times6 = 18$

Step2: Double it

$18\times2 = 36$

Step3: Add 2

$36 + 2 = 38$

Step4: Subtract 9

$38 - 9 = 29$

Step5: Add 9

$29 + 9 = 38$

Step6: Add tens and ones digit

Tens digit: 3, Ones digit: 8, $3 + 8 = 11$

Step7: Write the sum (for B and C, B is the tens digit of the sum, C is the ones digit? Wait, no, the instruction is "Write the sum". Wait, the sum is 11, but maybe I misread. Wait, let's re - check:

Wait, after step 5, we have 38. Then "Add the tens digit to the ones digit": 3 (tens) + 8 (ones) = 11. Then "Write the sum" – the sum is 11. But the boxes are B and C. Maybe B is the tens digit of the sum and C is the ones digit? So B is 1, C is 1? Wait, no, let's do it again:

Wait, initial number: 3 (imagine 3 in head)
Multiply by 6: 3*6 = 18
Double it: 18*2 = 36
Add 2: 36 + 2 = 38
Subtract 9: 38 - 9 = 29
Add 9: 29+9 = 38
Add tens digit (3) to ones digit (8): 3 + 8 = 11
Write the sum: 11. So if B and C are for the sum, B is 1, C is 1? Wait, maybe the problem is that B is the tens digit of the number before adding tens and ones, no, the last step is "Add the tens digit to the ones digit. Write the sum." So the sum is 11, so B is 1, C is 1? Wait, maybe I made a mistake in steps. Let's re - calculate:

Wait, "imagine 3 in your head"
Multiply 6: 3*6 = 18
Double it: 18*2 = 36
Add 2: 36 + 2 = 38
Subtract 9: 38 - 9 = 29
Add 9: 29 + 9 = 38
Add tens (3) and ones (8): 3+8 = 11
Write the sum: 11. So B is 1, C is 1?

Step1: Imagine 2, add 4

$2 + 4 = 6$

Step2: Multiply by 8

$6\times8 = 48$

Step3: Subtract 7

$48 - 7 = 41$

Step4: Write the tens digit

Tens digit of 41 is 4.

Answer:

1

Second Box (B and C)