Question

instructions: in each question, list the elements from least to greatest atomic radius. 1) carbon (c), lead (pb), silicon (si), tin (sn) 2) sulfur (s), silicon (si), argon (ar), sodium (na) 3) nickel (ni), titanium (ti), calcium (ca), barium (ba) 4) cesium (cs), potassium (k), sodium (na) 5) phosphorus (p), aluminum (al), magnesium (mg) 6) zinc (zn), oxygen (o), rubidium (rb)

Explanation:

Step1: Recall atomic - radius trends

Atomic radius increases down a group and decreases across a period from left to right.

Step2: Analyze each set of elements

For set 1 (Carbon (C), Lead (Pb), Silicon (Si), Tin (Sn))

Carbon is in period 2, Silicon in period 3, Tin in period 5 and Lead in period 6. So the order from least to greatest atomic radius is C < Si < Sn < Pb.

For set 2 (Sulfur (S), Silicon (Si), Argon (Ar), Sodium (Na))

They are all in period 3. From left - to - right across the period, the order is Ar < S < Si < Na.

For set 3 (Nickel (Ni), Titanium (Ti), Calcium (Ca), Barium (Ba))

Nickel is in period 4, Titanium in period 4, Calcium in period 4 and Barium in period 6. Among Ni, Ti and Ca in period 4, from left - to - right, the order is Ni < Ti < Ca. So the overall order is Ni < Ti < Ca < Ba.

For set 4 (Cesium (Cs), Potassium (K), Sodium (Na))

They are in group 1. As we go down the group, the atomic radius increases. So the order is Na < K < Cs.

For set 5 (Phosphorus (P), Aluminum (Al), Magnesium (Mg))

They are in period 3. From left - to - right, the order is P < Al < Mg.

For set 6 (Zinc (Zn), Oxygen (O), Rubidium (Rb))

Oxygen is in period 2, Zinc in period 4 and Rubidium in period 5. So the order is O < Zn < Rb.

Answer:

1. C < Si < Sn < Pb
2. Ar < S < Si < Na
3. Ni < Ti < Ca < Ba
4. Na < K < Cs
5. P < Al < Mg
6. O < Zn < Rb