Question

instructions: solve each problem to put the puzzle toget bob has a box of chocolates containing 6 chocolate covered almonds, 4 chocolate covered peanuts, and 8 plain chocolates. if the chocolates look identical, what is the probability that the first two chocolates bob eats will have almonds?

Explanation:

Step1: Calculate total chocolates

$6 + 4 + 8 = 18$

Step2: Probability first is almond

$\frac{6}{18} = \frac{1}{3}$

Step3: Probability second is almond

$\frac{5}{17}$

Step4: Multiply the two probabilities

$\frac{1}{3} \times \frac{5}{17} = \frac{5}{51}$

Answer:

$\frac{5}{51}$