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integrated chemistry physics s 2nd law using net force given the follow…

Question

integrated chemistry physics
s 2nd law using net force
given the following diagram, answer the following questions.
40 kg
60 n
300 n
net force =
acceleration =
check

Explanation:

Step1: Calculate net - force

The two forces act in the same direction. So, we add them.
$F_{net}=60\ N + 300\ N$

Step2: Calculate acceleration

According to Newton's second - law $F = ma$, where $F = F_{net}$, $m = 40\ kg$. Then $a=\frac{F_{net}}{m}$. First, we find $F_{net}=360\ N$, then $a=\frac{360\ N}{40\ kg}$.

Answer:

Net Force = $360\ N$
Acceleration = $9\ m/s^{2}$