Question

an ionic compound has the formula scbr₃. complete the table to determine the charge of the transition metal ion in this compound. enter a negative sign before negative numbers. positive numbers do not need a positive sign.
element | charge of one ion | total charge of ion(s) in compound | number of ion(s) in compound
scandium | blank | blank | blank
bromine | blank | blank | blank
*in one formula unit
what is the name of this ionic compound? blanks with dropdowns

Explanation:

Step1: Analyze Bromine Ion

Bromine (Br) is a halogen, so its ion has a charge of -1. In \( \text{ScBr}_3 \), the number of Br ions is 3. Total charge of Br ions: \( 3 \times (-1) = -3 \).

Step2: Determine Scandium Ion Charge

Ionic compounds are neutral, so total positive charge = total negative charge. Let Sc charge be \( x \). Number of Sc ions is 1. So \( x \times 1 + (-3) = 0 \), so \( x = +3 \). Total charge of Sc ions: \( 3 \) (since \( 1 \times 3 = 3 \)).

Step3: Fill Table

• Scandium: Charge of one ion = \( +3 \), Total charge = \( 3 \), Number of ions = \( 1 \)
• Bromine: Charge of one ion = \( -1 \), Total charge = \( -3 \), Number of ions = \( 3 \)

Step4: Name the Compound

For ionic compounds, name cation (Scandium, charge +3, so just scandium) then anion (bromide, since Br⁻). So name: Scandium bromide.

Answer:

Table Filling:

• Scandium: Charge of One Ion = \( 3 \), Total Charge of Ion(s) = \( 3 \), Number of Ion(s) = \( 1 \)
• Bromine: Charge of One Ion = \( -1 \), Total Charge of Ion(s) = \( -3 \), Number of Ion(s) = \( 3 \)

Compound Name: Scandium bromide