Question

an ionic compound is named copper (i) oxide. complete the table to determine the number of ions of each element in one formula unit of the compound. enter a negative sign before negative numbers. positive numbers do not need a positive sign.
element | charge of one ion | total charge of ion(s) in compound | number of ion(s) in compound
copper (i) | | |
oxygen | | |
*in one formula unit
what is the formula for the ionic compound?

Explanation:

Step1: Determine Copper(I) ion charge

Copper(I) means the charge of \( \text{Cu}^+ \) is \( +1 \).

Step2: Determine Oxygen ion charge

Oxygen typically forms \( \text{O}^{2-} \), so charge is \( -2 \).

Step3: Find total charge balance

In an ionic compound, total positive charge = total negative charge. Let number of \( \text{Cu}^+ \) be \( x \), \( \text{O}^{2-} \) be \( y \). So \( x(+1) + y(-2) = 0 \). The smallest integers: \( x = 2 \), \( y = 1 \). Total charge for Cu: \( 2\times(+1)=+2 \)? Wait, no: Wait, Cu(I) is \( +1 \), O is \( -2 \). To balance, 2 Cu⁺ (total +2) and 1 O²⁻ (total -2). So:

• Copper(I): Charge of one ion \( +1 \), total charge in compound \( +2 \)? No, wait, no: Wait, formula unit: Let's correct. For copper(I) oxide, the formula is \( \text{Cu}_2\text{O} \). So:
• Copper(I) ion: charge \( +1 \), number of ions \( 2 \), total charge \( 2\times(+1) = +2 \).
• Oxygen ion: charge \( -2 \), number of ions \( 1 \), total charge \( 1\times(-2) = -2 \).

Filling the table:

• Copper (I): Charge of One Ion: \( +1 \); Total Charge of Ion(s) in Compound: \( +2 \); Number of Ion(s) in Compound: \( 2 \).
• Oxygen: Charge of One Ion: \( -2 \); Total Charge of Ion(s) in Compound: \( -2 \); Number of Ion(s) in Compound: \( 1 \).

Formula: \( \text{Cu}_2\text{O} \) (so first dropdown: Cu, second: O with subscript 2? Wait, the formula is \( \text{Cu}_2\text{O} \), so the two ions are Cu⁺ (2 ions) and O²⁻ (1 ion).

Answer:

Table Filling:

• Copper (I):

Charge of One Ion: \( +1 \)
Total Charge of Ion(s) in Compound: \( +2 \)
Number of Ion(s) in Compound: \( 2 \)

• Oxygen:

Charge of One Ion: \( -2 \)
Total Charge of Ion(s) in Compound: \( -2 \)
Number of Ion(s) in Compound: \( 1 \)

Formula:

The formula for copper(I) oxide is \( \boldsymbol{\text{Cu}_2\text{O}} \) (so first box: Cu, second box: O with subscript 2, or as per dropdowns, likely "Cu" and "O" with the number of Cu as 2 and O as 1 in the formula, so the formula is \( \text{Cu}_2\text{O} \)).