Question

an ionic compound is named potassium hypobromite. complete the table to determine the number of ions of each type in one formula unit of the compound. enter a negative sign before negative numbers. positive numbers do not need a positive sign.
ion \tcharge of one ion \ttotal charge of ion(s) in compound \tnumber of ion(s) in compound
potassium \tyellow box \tyellow box \tyellow box
hypobromite \tyellow box \tyellow box \tyellow box
*in one formula unit
what is the formula for the ionic compound?
yellow dropdown yellow dropdown

Explanation:

Step1: Determine potassium ion charge

Potassium (K) is in Group 1, so its ion charge is $+1$.

Step2: Determine hypobromite ion charge

Hypobromite is $\ce{BrO^-}$, so its charge is $-1$.

Step3: Balance charges for compound

For a neutral compound, total positive charge = total negative charge. Let number of $\ce{K^+}$ be $x$ and $\ce{BrO^-}$ be $y$. Then $x(+1) + y(-1) = 0$. The simplest solution is $x = 1$, $y = 1$.

Step4: Fill table for potassium

Charge of one $\ce{K^+}$: $+1$; Total charge: $+1$ (since 1 ion); Number of ions: $1$.

Step5: Fill table for hypobromite

Charge of one $\ce{BrO^-}$: $-1$; Total charge: $-1$ (since 1 ion); Number of ions: $1$.

Step6: Determine formula

Using ion charges, formula is $\ce{KBrO}$.

Table Completion:

Ion	Charge of One Ion	Total Charge of Ion(s) in Compound	Number of Ion(s) in Compound
Hypobromite	$-1$	$-1$	$1$

Formula:

$\ce{KBrO}$

Answer:

(Table and Formula):

Table:

Ion	Charge of One Ion	Total Charge of Ion(s) in Compound	Number of Ion(s) in Compound
Hypobromite	$-1$	$-1$	$1$

Formula: $\ce{KBrO}$