Question

iron(iii) chromate
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part d
iron(iii) fluoride
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Explanation:

Iron(III) Chromate

Step1: Identify ions and charges

Iron(III) ion: $\text{Fe}^{3+}$, Chromate ion: $\text{CrO}_4^{2-}$

Step2: Balance charges

To balance, find LCM of 3 and 2, which is 6. So, 2 $\text{Fe}^{3+}$ (total +6) and 3 $\text{CrO}_4^{2-}$ (total -6).

Step3: Write formula

Combine ions: $\text{Fe}_2(\text{CrO}_4)_3$

Step1: Identify ions and charges

Iron(III) ion: $\text{Fe}^{3+}$, Fluoride ion: $\text{F}^-$

Step2: Balance charges

3 $\text{F}^-$ (total -3) balance 1 $\text{Fe}^{3+}$ (total +3).

Step3: Write formula

Combine ions: $\text{FeF}_3$

Answer:

$\text{Fe}_2(\text{CrO}_4)_3$

Iron(III) Fluoride