Question

1. an irregularly - shaped object is placed in a graduated cylinder already containing 25 ml of water. the water level rises to now read 45 ml. the recorded mass of the object is 13 grams. what is the density of the object? write your final answer with the correct number of significant figures in scientific notation. (5 pts.)
2. if 5 glurgs equals 1 quam, 2 bliks equals 3 donups, and 1 donup equals 4 quams, how many glurgs are there in 4 bliks? solve using dimensional analysis. (5 pts.)

Explanation:

Step1: Find object volume

Volume = 45 mL - 25 mL = 20 mL = 20 cm³

Step2: Calculate density

Density = 13 g / 20 cm³ = 0.65 g/cm³

Step3: Convert to scientific notation

0.65 = 6.5 × 10⁻¹ (2 significant figures)

Step1: Bliks to donups

4 bliks × (3 donups / 2 bliks) = 6 donups

Step2: Donups to quams

6 donups × (4 quams / 1 donup) = 24 quams

Step3: Quams to glurgs

24 quams × (5 glurgs / 1 quam) = 120 glurgs

Answer:

6.5 × 10⁻¹ g/cm³