Question

for items 3 - 5, use the figure shown. find the slope of each line in the figure. slope of p = slope of q = slope of r = slope of m = slope of n =

Explanation:

Step1: Recall slope formula

The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.

Step2: Find slope of line $p$

Let $(x_1,y_1)=(-4,8)$ and $(x_2,y_2)=(0, - 3)$. Then $m_p=\frac{-3 - 8}{0-(-4)}=\frac{-11}{4}=-2.75$.

Step3: Find slope of line $q$

Let $(x_1,y_1)=(0,6.2)$ and $(x_2,y_2)=(6.8,13)$. Then $m_q=\frac{13 - 6.2}{6.8-0}=\frac{6.8}{6.8}=1$.

Step4: Find slope of line $r$

Let $(x_1,y_1)=(4,-12)$ and $(x_2,y_2)=(12,0)$. Then $m_r=\frac{0-(-12)}{12 - 4}=\frac{12}{8}=1.5$.

Step5: Find slope of line $m$

Let $(x_1,y_1)=(-15.5,0)$ and $(x_2,y_2)=(0,6.2)$. Then $m_m=\frac{6.2-0}{0-(-15.5)}=\frac{6.2}{15.5}=0.4$.

Step6: Find slope of line $n$

Let $(x_1,y_1)=(-5,-6.8)$ and $(x_2,y_2)=(0.4,-3)$. Then $m_n=\frac{-3-(-6.8)}{0.4-(-5)}=\frac{3.8}{5.4}=\frac{19}{27}\approx0.704$.

Answer:

slope of $p=-2.75$
slope of $q = 1$
slope of $r=1.5$
slope of $m = 0.4$
slope of $n=\frac{19}{27}\approx0.704$