Question

in a jar there are 5 blue slips of paper, 3 green slips of paper, 2 black slips of paper, and 4 slips of paper that are blue and black. find the probabilities below
p(slip is green)
p (slip contains blue)
p (slip is not red)

Explanation:

Step1: Calculate total number of slips

Total = 5 (blue) + 3 (green) + 2 (black) + 4 (blue - black) = 14

Step2: Calculate P(slip is green)

P(slip is green)=$\frac{\text{Number of green slips}}{\text{Total number of slips}}=\frac{3}{14}$

Step3: Calculate P(slip contains blue)

Number of slips that contain blue = 5 (only blue) + 4 (blue - black)=9
P(slip contains blue)=$\frac{9}{14}$

Step4: Calculate P(slip is not red)

Since there are no red slips, all 14 slips are not red.
P(slip is not red)=$\frac{14}{14} = 1$

Answer:

P(slip is green) = $\frac{3}{14}$
P(slip contains blue) = $\frac{9}{14}$
P(slip is not red) = 1