Question

joaquin has created a small treasure map that is in the shape of a square. he decides to make a larger version of the map, and on this new map he increases each side by 6 inches. the area of this larger version of the map is 121 square inches. what are the dimensions of his original, smaller map?
○ 5 inches by 5 inches
○ 8 inches by 8 inches
○ 11 inches by 11 inches
○ 17 inches by 17 inches

Explanation:

Step1: Find side length of larger square

The area of a square is \( A = s^2 \), where \( s \) is the side length. For the larger map, \( A = 121 \), so \( s=\sqrt{121}=11 \) inches.

Step2: Find side length of original square

The larger side length is the original side length plus 6 inches. Let \( x \) be the original side length. Then \( x + 6=11 \), so \( x = 11 - 6 = 5 \) inches. So the original map is 5 inches by 5 inches.

Answer:

A. 5 inches by 5 inches