Question

julio has two bags of gummy candies. one at a time, he randomly pulled 8 pineapple, 5 lime, and 7 strawberry candies out of the first bag and put them back each time. he also randomly pulled 11 mango, 3 tamarind, and 6 watermelon candies out of the second bag and put them back each time. based on this information, what is the probability that julio will select a strawberry candy from the first bag and a tamarind candy from the second bag the next time he takes a candy from each bag? type a number in each box.

Explanation:

Answer:

First, find the total number of candies in the first bag: \(8 + 5+7=20\). The probability of selecting a strawberry - flavored candy from the first bag is \(\frac{7}{20}\).

Next, find the total number of candies in the second bag: \(11 + 3+6 = 20\). The probability of selecting a tamarind - flavored candy from the second bag is \(\frac{3}{20}\).

Since the events are independent, the probability of both events occurring is the product of their individual probabilities. So the probability is \(\frac{7}{20}\times\frac{3}{20}=\frac{21}{400}\)