Question

1. will karimas court fit in the 20 - by - 20 - meter square area the park directors designated for the court?
2. use your ruler to measure the scale drawing. record the measurements in the table. then determine the dimensions of the actual court.
3. explain how you know whether the court will fit.

Explanation:

1. Assume a scale factor:

• Since the problem doesn't give the scale factor, let's assume a common - sense scale factor. If we assume that 1 cm on the scale drawing represents 1 m in actual.

Step1: Calculate actual length of court

If 1 unit on scale drawing represents 1 m in actual, for the length of the court in the scale - drawing is 11.4 units. So the actual length \(L = 11.4\times1=11.4\) m.

Step2: Calculate actual width of court

The width of the court in the scale - drawing is 6.2 units. So the actual width \(W = 6.2\times1 = 6.2\) m.

Step3: Calculate actual hoop to 3 - point line distance

The hoop to 3 - point line distance in the scale - drawing is 3.3 units. So the actual distance \(H=3.3\times1 = 3.3\) m.

Step4: Calculate actual 3 - point line to side line distance

The 3 - point line to side line distance in the scale - drawing is 0.4 units. So the actual distance \(S = 0.4\times1=0.4\) m.

Answer:

Length of Court, \(L\)	Width of Court, \(W\)	Hoop to 3 - Point Line, \(H\)	3 - Point Line to Side Line, \(S\)

To determine if the court will fit in the 20 - by - 20 - meter square area:
Since the actual length \(L = 11.4\) m and actual width \(W = 6.2\) m, and \(11.4<20\) and \(6.2 < 20\), the court will fit in the 20 - by - 20 - meter square area.