Question

kevin and mark took a random sample of 100 pieces of trail mix to determine the number of peanuts, raisins, and almonds in a container. if each container of trail mix is known to have 40% peanuts, 40% almonds, and 20% raisins, which sample is a better representation of the actual population? kevins sample marks sample peanuts 74 45 raisins 10 17 almonds 16 38 kevins sample is more representative. marks sample is more representative. both are equally representative. neither is representative.

Explanation:

Step1: Calculate percentage of peanuts in Kevin's sample

$\frac{74}{100}\times100\% = 74\%$

Step2: Calculate percentage of peanuts in Mark's sample

$\frac{45}{100}\times100\%=45\%$

Step3: Calculate percentage of raisins in Kevin's sample

$\frac{10}{100}\times 100\% = 10\%$

Step4: Calculate percentage of raisins in Mark's sample

$\frac{17}{100}\times100\% = 17\%$

Step5: Calculate percentage of almonds in Kevin's sample

$\frac{16}{100}\times100\%=16\%$

Step6: Calculate percentage of almonds in Mark's sample

$\frac{38}{100}\times100\% = 38\%$

Step7: Compare with actual percentages

The actual percentages are 40% peanuts, 40% almonds and 20% raisins. Mark's sample percentages (45% peanuts, 17% raisins, 38% almonds) are closer to the actual population percentages.

Answer:

Mark's sample is more representative.