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Question
kuta software - infinite algebra 1
graphing absolute value functions
graph each equation.
- $y = |x - 2| - 4$
- $y = |x + 1|$
- $y = |x| + 1$
- $y = |x| + 2$
- $y = |x + 2|$
- $y = |x + 1| + 3$
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For each absolute value function, we use the parent function $y=|x|$ (vertex at $(0,0)$) and apply horizontal/vertical shifts:
- Horizontal shift: $y=|x-h|$ shifts $h$ units right if $h>0$, left if $h<0$
- Vertical shift: $y=|x|+k$ shifts $k$ units up if $k>0$, down if $k<0$
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1) $y=|x-2|-4$
Step1: Identify vertex
Vertex: $(2, -4)$
Step2: Find 2 additional points
For $x=0$: $y=|0-2|-4=2-4=-2$ → $(0,-2)$
For $x=4$: $y=|4-2|-4=2-4=-2$ → $(4,-2)$
Step3: Plot & connect points
Draw a V-shape through $(2,-4)$, $(0,-2)$, $(4,-2)$
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2) $y=|x+1|$
Step1: Identify vertex
Rewrite as $y=|x-(-1)|$, vertex: $(-1, 0)$
Step2: Find 2 additional points
For $x=0$: $y=|0+1|=1$ → $(0,1)$
For $x=-2$: $y=|-2+1|=1$ → $(-2,1)$
Step3: Plot & connect points
Draw a V-shape through $(-1,0)$, $(0,1)$, $(-2,1)$
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3) $y=|x|+1$
Step1: Identify vertex
Vertex: $(0, 1)$
Step2: Find 2 additional points
For $x=1$: $y=|1|+1=2$ → $(1,2)$
For $x=-1$: $y=|-1|+1=2$ → $(-1,2)$
Step3: Plot & connect points
Draw a V-shape through $(0,1)$, $(1,2)$, $(-1,2)$
---
4) $y=|x|+2$
Step1: Identify vertex
Vertex: $(0, 2)$
Step2: Find 2 additional points
For $x=1$: $y=|1|+2=3$ → $(1,3)$
For $x=-1$: $y=|-1|+2=3$ → $(-1,3)$
Step3: Plot & connect points
Draw a V-shape through $(0,2)$, $(1,3)$, $(-1,3)$
---
5) $y=|x+2|$
Step1: Identify vertex
Rewrite as $y=|x-(-2)|$, vertex: $(-2, 0)$
Step2: Find 2 additional points
For $x=0$: $y=|0+2|=2$ → $(0,2)$
For $x=-4$: $y=|-4+2|=2$ → $(-4,2)$
Step3: Plot & connect points
Draw a V-shape through $(-2,0)$, $(0,2)$, $(-4,2)$
---
6) $y=|x+1|+3$
Step1: Identify vertex
Rewrite as $y=|x-(-1)|+3$, vertex: $(-1, 3)$
Step2: Find 2 additional points
For $x=0$: $y=|0+1|+3=4$ → $(0,4)$
For $x=-2$: $y=|-2+1|+3=4$ → $(-2,4)$
Step3: Plot & connect points
Draw a V-shape through $(-1,3)$, $(0,4)$, $(-2,4)$
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