QUESTION IMAGE
Question
- kyle is doing a chemistry experiment and has 30 ml of a 25% solution. how many ml of a 80% solution should he add to obtain a mixture that is a 50% solution?
| amount | % | total | |
|---|---|---|---|
| solution 2 | x | 80 | 80x |
| mixture | x + 30 | 50 | 5(x + 30) |
Step1: Set up equation based on mixture principle
The amount of pure substance before mixing equals the amount of pure substance after mixing. For the first - solution, the amount of pure substance is \(30\times0.25 = 7.5\). For the second - solution, the amount of pure substance is \(0.8x\). And for the mixture, the amount of pure substance is \(0.5(x + 30)\). So the equation is \(30\times0.25+0.8x=0.5(x + 30)\).
Step2: Expand and simplify the equation
\[
$$\begin{align*}
7.5+0.8x&=0.5x+15\\
0.8x - 0.5x&=15 - 7.5
\end{align*}$$
\]
Step3: Solve for \(x\)
\[
$$\begin{align*}
0.3x&=7.5\\
x&=\frac{7.5}{0.3}\\
x& = 25
\end{align*}$$
\]
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